Blog Post #82: Terrific Talents!

Dear Readers,

With special permission, of course, in today’s blog post I am delighted to be featuring a high five terrific young talents! Most of them are students at Musica Mundi School, and are therefore outstanding young musicians. All of them are also highly capable in Mathematics.

The students are so fond of our clever cats that they let them be pictured first! ♥♥♥

In alphabetical order, the first letters of the five first names are:

C, K, P, Q, S.

Imagine swapping each of those letters for a number corresponding to the letter positions within the English alphabet.

That would give us:

3, 11, 16, 17, 19.

The four prime numbers there correspond perfectly to the four students at the music school! The composite number 16, in the middle, is uniquely special because 2 raised to the power of 4 or 4 raised to the power of 2 both make 16.

FUN GROUP CHALLENGE!

Is it possible to split the group of five numbers

3, 11, 16, 17, 19

into two mini-groups such that the sum of the numbers in both groups is the same?

An answer is given further down below, at the end of the article.

DO YOU LIKE FUN FORMULAS!?

(6n⁴-64n³+198n²-44n-24)÷24

=Surprise results for the students!

If n=1…calculate…the result is 3.

If n=2…calculate…the result is 11.

If n=3…calculate…the result is 16.

If n=4…calculate…the result is 17.

If n=5…calculate…the result is 19.

 

ANOTHER SNEAKY SURPRISE FOR A FRIEND!

Ruth B. already starred in Blog Post #81…but since then I learned that she likes ‘The Queen’s Gambit’ Netflix mini-series with the already world-famous character, Beth Harmon.

One fun anagram that’s possible by rearranging the letters of

U, BETH HARMON…?!

is…

NAME…? OH, RUTH B!

Until the next time…!

With very best wishes as always to everyone,

Paul Motwani xxx

P.S.=PUZZLE SOLUTION!

The answer is “YES!” because 3+11+19=16+17.